Gerrit Lohmann
April 12, 2021
Fluid dynamics, ocean circulation, wind-driven and thermohaline circulation; atmosphere dynamics, dynamical system theory, non-dimensional parameters, bifurcations and instabilities; Gravity, Rossby, and Kelvin waves; Conceptual models, Analytical and Programming techniques; Time series analysis
Lecture: April 12. (Monday), 14:00 Prof. Dr. Gerrit Lohmann
Tutorial: April 12. (Monday), 16:00 Justus Contzen and Lars Ackermann
Time required for Sheet 1: 8 h
Chapter The equations of fluid motion (Marchal and Plumb, 2008). (45 min)
Content in the script: Fluid Dynamics, Non-dimensional parameters, Dynamical similarity, Elimination of the pressure term and vorticity
Reading/learning (the sections with a star are voluntary). It might take 60 min.
Content of today's lecture (45 min)
Content of today's lecture:
Our fluid model describes:
\[ \rho \left( \frac{\partial \mathbf{u}}{\partial t} + \mathbf{u} \cdot \nabla \mathbf{u} \right) = -\nabla p + \nabla \cdot \mathbb{T} + \mathbf{F}, \]
\( \mathbf{u} \) velocity (a vector), \( \rho \) fluid density,
\( p \) pressure, \( \mathbb{T} \) the \( 3\times 3 \) (deviatoric) stress tensor,
\( \mathbf{F} \) represents body forces (per unit volume) acting on the fluid.
\[ \rho \left( \frac{\partial \mathbf{u}}{\partial t} + \mathbf{u} \cdot \nabla \mathbf{u} \right) = -\nabla p + \nabla \cdot \mathbb{T} + \mathbf{F}, \]
\( \mathbf{u} \) velocity (a vector), \( \rho \) fluid density,
\( p \) pressure, \( \mathbb{T} \) the \( 3\times 3 \) (deviatoric) stress tensor,
\( \mathbf{F} \) represents body forces (per unit volume) acting on the fluid.
This equation is often written using the substantive derivative (a statement of Newton's second law):
\[ \rho \frac{D \mathbf{u}}{D t} = -\nabla p + \nabla \cdot\mathbb{T} + \mathbf{F} \label{newtonzwei} \]
\[ \overbrace{\rho \Big( \underbrace{\frac{\partial \mathbf{u}}{\partial t}}_{ \begin{smallmatrix} \text{Unsteady}\\ \text{acceleration} \end{smallmatrix}} + \underbrace{\mathbf{u} \cdot \nabla \mathbf{u}}_{ \begin{smallmatrix} \text{Advective} \\ \text{acceleration} \end{smallmatrix}}\Big)}^{\text{Inertia (per volume)}} = \overbrace{\underbrace{-\nabla p}_{ \begin{smallmatrix} \text{Pressure} \\ \text{gradient} \end{smallmatrix}} + \underbrace{\nabla \cdot\mathbb{T}}_{\text{Viscosity}}}^{\text{Divergence of stress}} + \underbrace{\mathbf{F}}_{ \begin{smallmatrix} \text{Other} \\ \text{body} \\ \text{forces} \end{smallmatrix}} \]
\[ \overbrace{\rho \Big( \underbrace{\frac{\partial \mathbf{u}}{\partial t}}_{ \begin{smallmatrix} \text{Unsteady}\\ \text{acceleration} \end{smallmatrix}} + \underbrace{\mathbf{u} \cdot \nabla \mathbf{u}}_{ \begin{smallmatrix} \text{Advective} \\ \text{acceleration} \end{smallmatrix}}\Big)}^{\text{Inertia (per volume)}} = \overbrace{\underbrace{-\nabla p}_{ \begin{smallmatrix} \text{Pressure} \\ \text{gradient} \end{smallmatrix}} + \underbrace{\nabla \cdot\mathbb{T}}_{\text{Viscosity}}}^{\text{Divergence of stress}} + \underbrace{\mathbf{F}}_{ \begin{smallmatrix} \text{Other} \\ \text{body} \\ \text{forces} \end{smallmatrix}} \]
A very significant feature of the Navier-Stokes equations is the presence of advective acceleration:
\[ \mathbf{u} \cdot \nabla \mathbf{u} \]
(Script: A general framework as transport phenomenon.)
Components of stress in three dimensions.
\( \nabla p \) pressure gradient: isotropic part
\( \nabla \cdot\mathbb{T} \) anisotropic part describing viscous forces.
Model is needed relating the stresses to the fluid motion
Cauchy stress tensor: \[ \mathbb{T} = \left({\begin{matrix} \mathbf{T}^{(\mathbf{e}_1)} \\ \mathbf{T}^{(\mathbf{e}_2)} \\ \mathbf{T}^{(\mathbf{e}_3)} \\ \end{matrix}}\right) = \left({\begin{matrix} \sigma _{11} & \sigma _{12} & \sigma _{13} \\ \sigma _{21} & \sigma _{22} & \sigma _{23} \\ \sigma _{31} & \sigma _{32} & \sigma _{33} \\ \end{matrix}}\right) \equiv \left({\begin{matrix} \sigma _x & \tau _{xy} & \tau _{xz} \\ \tau _{yx} & \sigma _y & \tau _{yz} \\ \tau _{zx} & \tau _{zy} & \sigma _z \\ \end{matrix}}\right) \]
\( \tau \) are the shear stresses, and \( p=-{\frac{1}{3}}(\sigma_{x}+\sigma_{y}+\sigma_{z}) \)
From the Newton's third law (actio est reactio), symmetry \[ \mathbb{T} = \mathbb{T}^T \]
Components of stress in three dimensions.
Regardless of the flow assumptions, a statement of the conservation of mass is generally necessary. This is achieved through the mass continuity equation, given in its most general form as: \[ \frac{\partial \rho}{\partial t} + \nabla \cdot (\rho \mathbf{u}) = 0 \]
or, using the substantive derivative:
\[ \frac{D\rho}{Dt} + \rho (\nabla \cdot \mathbf{u}) = 0. \]
The temperature at a point 50 km north of a station is \( 3^oC \) cooler than at the station.
If the wind is blowing from the northeast at 20m/s
and the air is being heated by radiation at a rate of \( 1^oC/h \).
What is the local temperature change at the station?
The total change of temperature is given by
\[ \frac{d T}{dt} = \frac{\partial T}{\partial t} + {\bf u} \cdot \nabla T = \dot{q} \quad \Leftrightarrow \quad \frac{\partial T}{\partial t} = - {\bf u} \cdot \nabla T + \dot{q} \]
Here we use the velocity (from northeast)
\[ {\bf u} = - 20 \frac{m}{s} \cdot \frac{1}{\sqrt{2}} (1, 1, 0) , \quad \nabla T = \frac{{3}{^\circ C}}{{50}{km}} (0, -1, 0), \quad \dot{q} = 1 \frac{^\circ C}{h} \]
Then we calculate the temperature change at the station
\[ \frac{\partial T}{\partial t} = 20 \frac{m}{s} \, \frac{1}{\sqrt{2}} (1, 1, 0) \cdot (0, -1, 0) \frac{{3}{^\circ C}}{{50}{km}} + 1 \frac{^\circ C}{h} \approx {-2.1} \frac{^\circ C}{h} \]
\( \nabla \cdot \mathbb{T} \) becomes \( \mu \nabla^2 \mathbf{u} \) with \( \mu \) dynamic viscosity.
\[ \rho \left(\frac{\partial \mathbf{u}}{\partial t} + \mathbf{u} \cdot \nabla \mathbf{u}\right) = -\nabla p + \mu \nabla^2 \mathbf{u} + \mathbf{F}. \label{reyn0} \]
The vector field \( \mathbf{F} \) represents “other” (body force) forces. Typically gravity, but may include other fields (such as electromagnetic).
Often, these forces may be represented as the gradient of some scalar quantity. E.g.: Gravity in the z direction is the gradient of \( - \rho gz \)
Since pressure shows up only as a gradient, this implies that solving a problem without any such body force: include the body force by modifying pressure
\[ \overbrace{\rho \Big( \underbrace{\frac{\partial \mathbf{u}}{\partial t}}_{ \begin{smallmatrix} \text{Unsteady}\\ \text{acceleration} \end{smallmatrix}} + \underbrace{\mathbf{u} \cdot \nabla \mathbf{u}}_{ \begin{smallmatrix} \text{Advective} \\ \text{acceleration} \end{smallmatrix}}\Big)}^{\text{Inertia (per volume)}} = \overbrace{\underbrace{-\nabla p}_{ \begin{smallmatrix} \text{Pressure} \\ \text{gradient} \end{smallmatrix}} + \underbrace{\mu \nabla^2 \mathbf{u}}_{\text{Viscosity}}}^{\text{Divergence of stress}} + \underbrace{\mathbf{F}}_{ \begin{smallmatrix} \text{Other} \\ \text{body} \\ \text{forces} \end{smallmatrix}} \]
If temperature effects are also neglected, the only “other” equation: mass continuity equation. Under the incompressible assumption, density is a constant and it follows that the equation will simplify to:
\[ \nabla \cdot \mathbf{u} = 0 \qquad . \label{consmass} \]
This becomes a statement of the conservation of volume !
2D: assume \( w = 0 \) and no dependence of anything on z
\[ \rho \left(\frac{\partial u}{\partial t} + u \frac{\partial u}{\partial x} + v \frac{\partial u}{\partial y}\right) = -\frac{\partial p}{\partial x} + \mu \left(\frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2}\right) \] \[ \rho \left(\frac{\partial v}{\partial t} + u \frac{\partial v}{\partial x} + v \frac{\partial v}{\partial y}\right) = -\frac{\partial p}{\partial y} + \mu \left(\frac{\partial^2 v}{\partial x^2} + \frac{\partial^2 v}{\partial y^2}\right) \]
Differentiating the first with respect to y: \( \quad \partial_y \)
the second with respect to x: \( \quad \partial_x \)
and subtracting the resulting equations will eliminate pressure and any potential force.
Defining the stream function through \[ u = \frac{\partial \psi}{\partial y} \quad ; \quad v = -\frac{\partial \psi}{\partial x} \]
results in mass continuity being unconditionally satisfied:
\[ \frac{\partial}{\partial t}\left(\nabla^2 \psi\right) + \frac{\partial \psi}{\partial y} \frac{\partial}{\partial x}\left(\nabla^2 \psi\right) - \frac{\partial \psi}{\partial x} \frac{\partial}{\partial y}\left(\nabla^2 \psi\right) = \nu \nabla^4 \psi \]
or using the total derivative
\[ D_t \left(\nabla^2 \psi\right) = \nu \nabla^4 \psi \]
\( \nu \) the kinematic viscosity \( \nu=\frac{\mu}{\rho}. \)
This single equation describes 2D fluid flow !
kinematic viscosity as parameter!
incompressible flow, temperature effects are negligible and external forces are neglected.
conservation of mass \[ \nabla \cdot \mathbf{u} = 0 \] conservation of momentum \[ \partial_t \mathbf{u} + ( \mathbf{u} \cdot \nabla) \mathbf{u} = - \frac{1}{\rho_0} \nabla p + \nu \nabla^2 \mathbf{u} \]
The equations can be made dimensionless by a length-scale L, determined by the geometry of the flow, and by a characteristic velocity U.
For analytical solutions, numerical results, and experimental measurements, it is useful to report the results in a dimensionless system (concept of dynamic similarity).
Representative values for velocity (U), time (T), distances (L). Using these values, the values in the dimensionless-system (written with subscript d) can be defined: \[ u =U \cdot u_d \] \[ t = T \cdot t_d \] \[ x = L \cdot x_d \] with \( U = L/T \).
From these scalings, we can also derive
\[ \partial_t = \frac{\partial}{\partial t } = \frac{1}{T} \cdot \frac{\partial}{\partial t_d } \] \[ \partial_x = \frac{\partial}{\partial x} = \frac{1}{L} \cdot \frac{\partial}{\partial x_d } \]
Note furthermore the units of \( [\rho_0] = kg/m^3, [p] = kg/(m s^2), [p]/[\rho_0]= {m^2}/{s^2} \)
Therefore the pressure gradient term has the scaling \( U^2/L \).
\[ \nabla_d \cdot \mathbf{u_d} = 0 \] and conservation of momentum \[ \frac{\partial}{\partial t_d } \mathbf{u_d} + ( \mathbf{u_d} \cdot \nabla_d) \mathbf{u_d} = - \nabla_d p_d + \frac{1}{Re} \nabla_d^2 \mathbf{u_d} \] The dimensionless parameter \[ Re=UL/ \nu \]
is the Reynolds number and the only parameter left!
For large Reynolds numbers, the flow is turbulent. \( Re \sim (10^4-10^8) \). Flow develops steep gradients locally.
In the literature: “equations have been made dimensionless”, means that our procedure is applied and the subscripts d are dropped.
These numbers can be interpreted as follows:
Reading/learning might take 45 min.
based on Chapter 1 from Holton and Hakim (2013)
Reading/learning might take 60 min.
Workload /credit points: 3 CP, 90 h
50% of the points of the exercise sheets are required. Furthermore, we require active participation with at least one time showing a solution in the chat room. Working in study groups is encouraged, but each student is responsible for his/her own solution. If the solution is typewritten (e.g. with LaTex, Rmarkdown, or word), we allow up to 3 persons to be listed on a solution sheet.
The exam is based on the exercises and the general content of the lecture. The procedure follows the rules of pep.